x^2+30x+53=0

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Solution for x^2+30x+53=0 equation:


Simplifying
x2 + 30x + 53 = 0

Reorder the terms:
53 + 30x + x2 = 0

Solving
53 + 30x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-53' to each side of the equation.
53 + 30x + -53 + x2 = 0 + -53

Reorder the terms:
53 + -53 + 30x + x2 = 0 + -53

Combine like terms: 53 + -53 = 0
0 + 30x + x2 = 0 + -53
30x + x2 = 0 + -53

Combine like terms: 0 + -53 = -53
30x + x2 = -53

The x term is 30x.  Take half its coefficient (15).
Square it (225) and add it to both sides.

Add '225' to each side of the equation.
30x + 225 + x2 = -53 + 225

Reorder the terms:
225 + 30x + x2 = -53 + 225

Combine like terms: -53 + 225 = 172
225 + 30x + x2 = 172

Factor a perfect square on the left side:
(x + 15)(x + 15) = 172

Calculate the square root of the right side: 13.114877049

Break this problem into two subproblems by setting 
(x + 15) equal to 13.114877049 and -13.114877049.

Subproblem 1

x + 15 = 13.114877049 Simplifying x + 15 = 13.114877049 Reorder the terms: 15 + x = 13.114877049 Solving 15 + x = 13.114877049 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-15' to each side of the equation. 15 + -15 + x = 13.114877049 + -15 Combine like terms: 15 + -15 = 0 0 + x = 13.114877049 + -15 x = 13.114877049 + -15 Combine like terms: 13.114877049 + -15 = -1.885122951 x = -1.885122951 Simplifying x = -1.885122951

Subproblem 2

x + 15 = -13.114877049 Simplifying x + 15 = -13.114877049 Reorder the terms: 15 + x = -13.114877049 Solving 15 + x = -13.114877049 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-15' to each side of the equation. 15 + -15 + x = -13.114877049 + -15 Combine like terms: 15 + -15 = 0 0 + x = -13.114877049 + -15 x = -13.114877049 + -15 Combine like terms: -13.114877049 + -15 = -28.114877049 x = -28.114877049 Simplifying x = -28.114877049

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-1.885122951, -28.114877049}

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